在GNU编译器下根据系统预置宏，正确识别是否支持char8_t。（注：仅根据文档实现，待LINUX下测试）

inc/hgl/platform/compiler/DataTypeGNU.h

@@ -17,5 +17,12 @@ namespace hgl
 
     using float32   =float;
     using float64   =double;
+
+#if defined(__cpp_char8_t)||defined(__cpp_lib_char8_t)
+    #define HGL_SUPPORT_CHAR8_T
+    using u8char = char8_t;
+#else
+    using u8char = char;
+#endif
 }//namespace hgl
 #endif//HGL_DATATYPE_GNU_INCLUDE

inc/hgl/platform/compiler/GNU.h

@@ -72,14 +72,6 @@
 
 #endif//__GNUC__
 
-// 假设 GCC 从 11 开始正式支持 char8_t( 这个我手头没有 11 ，不确定 )
-#if __GNUC__ >= 11
-    using u8char = char8_t;
-#else
-    using u8char = char;
-#endif
-
-
 #define HGL_THREAD_LOCAL_STORAGE        __thread                                //线程本地储存
 //--------------------------------------------------------------------------------------------------
 #define HGL_LIB_FRONT   HGL_LIB_OS "_" HGL_LIB_COMPILER_NAME "_" HGL_LIB_DEBUG_NAME "_"

inc/hgl/platform/compiler/Microsoft.h

@@ -21,9 +21,10 @@
 #define HGL_THREAD_LOCAL_STORAGE        __declspec(thread)                              //线程本地储存
 //--------------------------------------------------------------------------------------------------
 #if _MSVC_LANG>=201704L         //C++20
-using u8char    =char8_t;
+    #define HGL_SUPPORT_CHAR8_T
+    using u8char    =char8_t;
 #else
-using u8char    =char;
+    using u8char    =char;
 #endif
 
 #define HGL_FMT_I64            "%I64d"